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{
"metadata": {
"kernelspec": {
"display_name": "Python 3 (ipykernel)",
"language": "python",
"name": "python3"
},
"language_info": {
"codemirror_mode": {
"name": "ipython",
"version": 3
},
"file_extension": ".py",
"mimetype": "text/x-python",
"name": "python",
"nbconvert_exporter": "python",
"pygments_lexer": "ipython3",
"version": "3.8.10"
}
},
"nbformat": 4,
"nbformat_minor": 1,
"cells": [
{
"cell_type": "markdown",
"metadata": {
"lang": "fr"
},
"source": [
"# Linalg (linear algebra)\n",
"\n",
"Numpy intègre le calcul matriciel (ou l'algèbre linéaire) dans sa sous-bibliothèque [numpy.linalg](https://docs.scipy.org/doc/numpy/reference/routines.linalg.html). Pour être efficace il est\n",
"important que Numpy soit relié aux bibliothèques [Lapack](https://www.netlib.org/lapack/) et [BLAS](https://www.netlib.org/blas/) (la version d'Intel est [MKL](https://www.intel.com/content/www/us/en/developer/tools/oneapi/onemkl.html)). Ces bibliothèques sont imbatables, Numpy relié à ces bibliothèques sera largement plus rapide qu'un programme dans n'importe quel autre langage qui ne les utilise pas (vous relevez le défi ?).\n",
"\n",
"La bibliothèque [Scipy](https://scipy.org/) a aussi une sous-bibliothèque [linalg](https://docs.scipy.org/doc/scipy/reference/linalg.html) qui est très proches. Si vous ne trouvez pas\n",
"ce que vous cherchez dans la version de Numpy, il peut être intéressant de regarder si Scipy l'a."
]
},
{
"cell_type": "code",
"execution_count": 1,
"metadata": {},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"blas_mkl_info:\n",
" NOT AVAILABLE\n",
"blis_info:\n",
" NOT AVAILABLE\n",
"openblas_info:\n",
" libraries = ['openblas', 'openblas']\n",
" library_dirs = ['/usr/local/lib']\n",
" language = c\n",
" define_macros = [('HAVE_CBLAS', None)]\n",
" runtime_library_dirs = ['/usr/local/lib']\n",
"blas_opt_info:\n",
" libraries = ['openblas', 'openblas']\n",
" library_dirs = ['/usr/local/lib']\n",
" language = c\n",
" define_macros = [('HAVE_CBLAS', None)]\n",
" runtime_library_dirs = ['/usr/local/lib']\n",
"lapack_mkl_info:\n",
" NOT AVAILABLE\n",
"openblas_lapack_info:\n",
" libraries = ['openblas', 'openblas']\n",
" library_dirs = ['/usr/local/lib']\n",
" language = c\n",
" define_macros = [('HAVE_CBLAS', None)]\n",
" runtime_library_dirs = ['/usr/local/lib']\n",
"lapack_opt_info:\n",
" libraries = ['openblas', 'openblas']\n",
" library_dirs = ['/usr/local/lib']\n",
" language = c\n",
" define_macros = [('HAVE_CBLAS', None)]\n",
" runtime_library_dirs = ['/usr/local/lib']\n",
"Supported SIMD extensions in this NumPy install:\n",
" baseline = SSE,SSE2,SSE3\n",
" found = SSSE3,SSE41,POPCNT,SSE42,AVX,F16C,FMA3,AVX2\n",
" not found = AVX512F,AVX512CD,AVX512_KNL,AVX512_KNM,AVX512_SKX,AVX512_CLX,AVX512_CNL,AVX512_ICL\n"
]
}
],
"source": [
"import numpy as np\n",
"import numpy.linalg as lin\n",
"\n",
"np.set_printoptions(precision=3)\n",
"np.show_config()"
]
},
{
"cell_type": "markdown",
"metadata": {
"collapsed": true,
"lang": "fr"
},
"source": [
"## Opérations de base\n",
"\n",
"On a vu que les opérateurs +, -, \\* et / sont appliqués terme à terme ce qui est juste pour + et - dans le cadre du calcul matriciel mais pas pour \\* et /.\n",
"\n",
"* Le __produit scalaire__ utilise la méthode `dot` ou l'opérateur `@`\n",
"* La division que l'on peut imaginer comme \n",
" * la __résolution__ d'un système matriciel utilise la fonction `solve`\n",
" * le calcul de l'__inverse__ de la matrice utilise la fonction `inv`"
]
},
{
"cell_type": "code",
"execution_count": 2,
"metadata": {},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"multiplication terme à terme : \n",
" [[ 1 4]\n",
" [ 9 16]]\n",
"produit matriciel : \n",
" [[ 7 10]\n",
" [15 22]]\n"
]
}
],
"source": [
"A = np.array([[1,2],[3,4]])\n",
"print(\"multiplication terme à terme : \\n\",A * A) # tous les opérateurs sont appliqués terme à terme\n",
"print(\"produit matriciel : \\n\", A.dot(A)) # A @ A can be used too"
]
},
{
"cell_type": "markdown",
"metadata": {
"lang": "fr"
},
"source": [
"Résolution de système matriciel :"
]
},
{
"cell_type": "code",
"execution_count": 3,
"metadata": {},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"x = [3. 7.]\n",
"verification : [17. 37.]\n"
]
}
],
"source": [
"b = np.array([17,37])\n",
"x = lin.solve(A, b) # bien mieux que de calculer la matrice inverse (plus rapide et plus stable)\n",
"print(\"x = \", x)\n",
"print(\"verification : \", A @ x)"
]
},
{
"cell_type": "markdown",
"metadata": {
"lang": "fr"
},
"source": [
"Si on le désire vraiment, on peut calculer la matrice inverse (mais c'est plus long) :"
]
},
{
"cell_type": "code",
"execution_count": 4,
"metadata": {},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"A⁻¹ :\n",
" [[-2. 1. ]\n",
" [ 1.5 -0.5]]\n",
"x = [3. 7.]\n"
]
}
],
"source": [
"print(\"A⁻¹ :\\n\", lin.inv(A)) # la matrice inverse\n",
"print(\"x = \", lin.inv(A).dot(b))"
]
},
{
"cell_type": "markdown",
"metadata": {
"lang": "fr"
},
"source": [
"Enfin __la transposée__ est simplement `T` :"
]
},
{
"cell_type": "code",
"execution_count": 5,
"metadata": {},
"outputs": [
{
"data": {
"text/plain": [
"array([[1, 3],\n",
" [2, 4]])"
]
},
"execution_count": 5,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"A.T"
]
},
{
"cell_type": "markdown",
"metadata": {
"lang": "fr"
},
"source": [
"## Extractions\n",
"\n",
"On peut récupérer\n",
"\n",
"* la diagonale d'une matrice avec la fonction `diag` (attention le résultat est un vecteur si l'argument est une matrice et une matrice si l'argument est un vecteur)\n",
"* la matrice triangulaire inférieur avec la fonction `tril` (l pour lower) et supérieure avec `triu` (u pour upper). Il est possible de décaler la diagonale du triangle, voir la doc\n",
"\n",
"On peut aussi construire une matrice triangulaire avec des 1 et 0 avec `tri`et donc aussi une matrice triangulaire quelconque :"
]
},
{
"cell_type": "code",
"execution_count": 6,
"metadata": {},
"outputs": [
{
"data": {
"text/plain": [
"array([[4., 0., 0.],\n",
" [8., 9., 0.],\n",
" [5., 5., 4.]])"
]
},
"execution_count": 6,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"np.tri(3,3) * np.random.randint(1, 10, size=(3,3))"
]
},
{
"cell_type": "markdown",
"metadata": {
"lang": "fr"
},
"source": [
"Et voici comme extraire une matrice tridiagonale :"
]
},
{
"cell_type": "code",
"execution_count": 7,
"metadata": {},
"outputs": [
{
"data": {
"text/plain": [
"array([[3, 7, 0, 0, 0],\n",
" [6, 1, 8, 0, 0],\n",
" [0, 3, 5, 9, 0],\n",
" [0, 0, 4, 4, 7],\n",
" [0, 0, 0, 6, 3]])"
]
},
"execution_count": 7,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"A = np.random.randint(1, 10, size=(5,5))\n",
"np.tril(np.triu(A, k=-1), k=1)"
]
},
{
"cell_type": "markdown",
"metadata": {
"lang": "fr"
},
"source": [
"## Opérations sur la matrice\n",
"\n",
"La bibliothèque offre des fonctions de\n",
"\n",
"* décomposition (LU, Choleski, QR, SVD...)\n",
"* valeurs et vecteurs propres\n",
"* norme, déterminant, conditionnement et rang"
]
},
{
"cell_type": "code",
"execution_count": 8,
"metadata": {},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"[[-0.349 0.585 0.132 0.359 0.624]\n",
" [-0.697 -0.557 0.221 -0.298 0.257]\n",
" [-0.465 -0.061 -0.052 0.668 -0.576]\n",
" [-0.349 0.585 0.132 -0.564 -0.447]\n",
" [-0.232 0.036 -0.956 -0.134 0.115]] \n",
"\n",
" [[ -8.602 -7.44 -10.927 -13.252 -10.23 ]\n",
" [ 0. 7.527 -0.039 3.907 7.559]\n",
" [ 0. 0. 1.61 -3.513 -0.301]\n",
" [ 0. 0. 0. 4.333 0.656]\n",
" [ 0. 0. 0. 0. 1.302]]\n",
"\n",
"Vérification :\n",
" [[3. 7. 4. 8. 9.]\n",
" [6. 1. 8. 5. 3.]\n",
" [4. 3. 5. 9. 4.]\n",
" [3. 7. 4. 4. 7.]\n",
" [2. 2. 1. 6. 3.]]\n"
]
}
],
"source": [
"Q,R = lin.qr(A) # Q est orthogonale, R est triangulaire supérieur\n",
"print(Q, '\\n\\n', R)\n",
"print(\"\\nVérification :\\n\", Q.dot(R))"
]
},
{
"cell_type": "markdown",
"metadata": {
"lang": "fr"
},
"source": [
"#### Valeurs propres et vecteurs propres"
]
},
{
"cell_type": "code",
"execution_count": 9,
"metadata": {},
"outputs": [
{
"data": {
"text/plain": [
"(array([23.099+0.j , -3.442+1.822j, -3.442-1.822j, -1.408+0.j ,\n",
" 1.192+0.j ]),\n",
" array([[-0.547+0.j , -0.191+0.047j, -0.191-0.047j, -0.51 +0.j ,\n",
" 0.487+0.j ],\n",
" [-0.457+0.j , -0.035-0.466j, -0.035+0.466j, -0.462+0.j ,\n",
" -0.423+0.j ],\n",
" [-0.476+0.j , 0.441+0.128j, 0.441-0.128j, 0.41 +0.j ,\n",
" -0.519+0.j ],\n",
" [-0.447+0.j , -0.536+0.j , -0.536-0.j , -0.167+0.j ,\n",
" -0.101+0.j ],\n",
" [-0.257+0.j , 0.435+0.233j, 0.435-0.233j, 0.575+0.j ,\n",
" 0.552+0.j ]]))"
]
},
"execution_count": 9,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"lin.eig(A) # donne les valeurs propres et les vecteurs propres de A"
]
},
{
"cell_type": "markdown",
"metadata": {
"lang": "fr"
},
"source": [
"#### Déterminant, norme etc. "
]
},
{
"cell_type": "code",
"execution_count": 10,
"metadata": {},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Déterminant : -587.9999999999999\n",
"Norme 2 : 26.343879744638983 \n",
"Norme 1 : 32.0\n",
"Conditionnement : 35.929347867977604\n"
]
}
],
"source": [
"print(\"Déterminant :\", lin.det(A))\n",
"print(\"Norme 2 :\", lin.norm(A), \"\\nNorme 1 :\", lin.norm(A, 1) )\n",
"print(\"Conditionnement :\", lin.cond(A,2)) # I choose norm 2 to compute the condition number"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": []
}
]
}
|